JEE MainMathematicsFunctionsNumerical+4 / −1
Let A = {a, b, c} and B = {1, 2, 3, 4}. Then the number of elements in the set C = {f : A B | 2 f(A) and f is not one-one} is .
Numerical answer
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Correct answer: 19
We need to count the number of functions where such that:
- , i.e. at least one element of maps to .
- is not one-one.
1. Total number of functions from to
Each of the elements of can map to any of the elements of . So total functions are
2. Count functions with
We want functions where appears at least once in the image.
Use complement counting:
- Total functions:
- Functions with no element mapped to : each element has only choices
So such functions are Hence functions with are
3. From these, remove the one-one functions
Now count injective functions such that .
Since and , the number of one-one functions from to is
Among these, count those containing in the image. Again use complement:
- Total injective functions:
- Injective functions avoiding : then image must lie in , and since domain has elements, all three must be used.
Number of such injective functions:
Therefore injective functions with are
4. Required count: not one-one and
So the required number is
5. Final answer
The number of elements in the set is
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