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Definite Integration question

2025 · 4 Apr · Shift 2 · Q42
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  5. /2025 · 4 Apr · Shift 2 · Q42

Definite Integration question

2025 · 4 Apr · Shift 2 · Q42

JEE MainMathematicsDefinite IntegrationMCQ+4 / −1
Let f(x)+2f(1x)=x2+5f(x)+2 f\left(\frac{1}{x}\right)=x^2+5f(x)+2f(x1​)=x2+5 and 2g(x)−3g(12)=x,x>02 g(x)-3 g\left(\frac{1}{2}\right)=x, x\gt 02g(x)−3g(21​)=x,x>0. If α=∫12f(x)dx\alpha=\int_1^2 f(x) \mathrm{d} xα=∫12​f(x)dx, and β=∫12g(x)dx\beta=\int_1^2 g(x) \mathrm{d} xβ=∫12​g(x)dx, then the value of 9α+β9 \alpha+\beta9α+β is :
  1. A
    0
  2. B
    10
  3. C
    1
  4. D
    11
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