JEE MainMathematicsDefinite IntegrationMCQ+4 / −1The solution for xxx of the equation ∫2xdttt2−1=π2\int\limits_{\sqrt 2 }^x {{{dt} \over {t\sqrt {{t^2} - 1} }} = {\pi \over 2}}2∫xtt2−1dt=2π isA32{{\sqrt 3 } \over 2}23B222\sqrt 222C222DNoneAttempt in chatSharePreviousNextMore from Definite IntegrationLet F(x)=f(x)+f(x1), where f(x)=l∫x1+tlogtdt, Then F(e) equals2007 · MCQThe value of 1∫a[x]f′(x)dx,a>1 where [x] denotes the greatest integer not exceeding x is2006 · MCQ0∫πxf(sinx)dx is equal to2006 · MCQ−23π∫−2π[(x+π)3+cos2(x+3π)]dx is equal to2006 · MCQLet f:R→R be a differentiable function having f(2)=6, f′(2)=(481). Then x→2lim6∫f(x)x−24t3dt…2005 · MCQThe value of −π∫π1+axcos2dx,a>0, is2005 · MCQIf I1=0∫12x2dx,I2=0∫12x3dx,I3=1∫22x2dx and I4=1∫22x3dx then2005 · MCQThe value of integral, 3∫69−x+xxdx is2005 · MCQ