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Circle question

2022 · 28 Jun · Shift 2 · Q43

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PYQ Library
JEE Main
Mathematics
Circle
2022 · 28 Jun · Shift 2 · Q43

Circle question

2022 · 28 Jun · Shift 2 · Q43

JEE MainMathematicsCircleNumerical+4 / −1

If one of the diameters of the circle

{x^2} + {y^2} - 2\sqrt 2 x - 6\sqrt 2 y + 14 = 0

is a chord of the circle

{(x - 2\sqrt 2 )^2} + {(y - 2\sqrt 2 )^2} = {r^2}

, then the value of r2 is equal to

\underline{\hspace{2cm}}

.

Numerical answer

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