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Binomial Theorem question

2002 · Shift 0 · Q105
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Binomial Theorem question

2002 · Shift 0 · Q105

JEE MainMathematicsBinomial TheoremMCQ+4 / −1
The coefficients of xp{x^p}xp and xq{x^q}xq in the expansion of (1+x)p+q{\left( {1 + x} \right)^{p + q}}(1+x)p+q are
  1. A
    equal
  2. B
    equal with opposite signs
  3. C
    reciprocals of each other
  4. D
    none of these
View written solutionFree

Correct answer: A

  1. Write the general term in the expansion

For (1+x)p+q,(1+x)^{p+q},(1+x)p+q, the coefficient of xrx^rxr is (p+qr).\binom{p+q}{r}.(rp+q​).

So:

  • Coefficient of xpx^pxp is (p+qp).\binom{p+q}{p}.(pp+q​).
  • Coefficient of xqx^qxq is (p+qq).\binom{p+q}{q}.(qp+q​).
  1. Use the symmetry property of binomial coefficients

We know that (nr)=(nn−r).\binom{n}{r}=\binom{n}{n-r}.(rn​)=(n−rn​).

Here, taking n=p+qn=p+qn=p+q: (p+qp)=(p+q(p+q)−p)=(p+qq).\binom{p+q}{p}=\binom{p+q}{(p+q)-p}=\binom{p+q}{q}.(pp+q​)=((p+q)−pp+q​)=(qp+q​).

Thus, the coefficients of xpx^pxp and xqx^qxq are equal.

  1. Check the options
  • A: equal — Correct
  • B: equal with opposite signs — Incorrect, because all coefficients in (1+x)p+q(1+x)^{p+q}(1+x)p+q are positive
  • C: reciprocals of each other — Incorrect
  • D: none of these — Incorrect

Therefore, the correct option is: A\boxed{A}A​

  1. Comparison with stored correct answer

Stored correct answer: A

My derived answer is also A, so they agree.

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