New chat PYQ Library Doubts Rank report

Sign in to see Recents

Sign in to save progress →

Area Under the Curves question

2025 · 2 Apr · Shift 1 · Q48

Guest · try one question or challengeGuest · try one question or challenge

PYQ Library
JEE Main
Mathematics
Area Under the Curves
2025 · 2 Apr · Shift 1 · Q48

Area Under the Curves question

2025 · 2 Apr · Shift 1 · Q48

JEE MainMathematicsArea Under the CurvesNumerical+4 / −1

If the area of the region

\left\{(x, y):\left|4-x^2\right| \leq y \leq x^2, y \leq 4, x \geq 0\right\}

is

\left(\frac{80 \sqrt{2}}{\alpha}-\beta\right), \alpha, \beta \in \mathbf{N}

, then

\alpha+\beta

is equal to

\underline{\hspace{2cm}}

.

Numerical answer

More from Area Under the Curves

The area of the region bounded by the curve $y = max {∣ x ∣, x ∣ x - 2∣}$ , the $x$ -axis and the lines $x = - 2$ and $x = 4$ is equal to 2025 · Numerical
The area of the region ${(x, y) : ∣ x - y ∣ \leq y \leq 4 x}$ is2025 · MCQ
Let $f : [0, \infty) \to R$ be a differentiable function such that $f (x) = 1 - 2 x + \int_{0}^{x} e^{x - t} f (t) d t$ for all $x \in [0, \infty)$ . Then the area of the region bounded by $y = f (x)$ and the coordinate axes is2025 · MCQ
If the area of the region ${(x, y) : ∣ x - 5∣ \leq y \leq 4 x}$ is , then $3 A$ is equal to .2025 · Numerical
If the area of the region bounded by the curves $y = 4 - \frac{x ^{2}}{4}$ and $y = \frac{x - 4}{2}$ is equal to $α$ , then $6 α$ . equals2025 · MCQ
If the area of the region ${(x, y) : 1 + x^{2} \leq y \leq min {x + 7, 11 - 3 x}}$ is $A$ , then $3 A$ is equal to :2025 · MCQ
Let the area of the bounded region ${(x, y) : 0 \leq 9 x \leq y^{2}, y \geq 3 x - 6}$ be . Then $6 A$ is equal to .2025 · Numerical
The area of the region, inside the circle $(x - 23)^{2} + y^{2} = 12$ and outside the parabola $y^{2} = 23 x$ is :2025 · MCQ