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Area Under the Curves question

2022 · 29 Jun · Shift 2 · Q38
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  5. /2022 · 29 Jun · Shift 2 · Q38

Area Under the Curves question

2022 · 29 Jun · Shift 2 · Q38

JEE MainMathematicsArea Under the CurvesNumerical+4 / −1
For real numbers a, b (a > b > 0), let Area {(x,y):x2+y2≤a2 and x2a2+y2b2≥1}=30π\left\{ {(x,y):{x^2} + {y^2} \le {a^2}\,and\,{{{x^2}} \over {{a^2}}} + {{{y^2}} \over {{b^2}}} \ge 1} \right\} = 30\pi{(x,y):x2+y2≤a2anda2x2​+b2y2​≥1}=30π and Area {(x,y):x2+y2≤b2 and x2a2+y2b2≤1}=18π\left\{ {(x,y):{x^2} + {y^2} \le {b^2}\,and\,{{{x^2}} \over {{a^2}}} + {{{y^2}} \over {{b^2}}} \le 1} \right\} = 18\pi{(x,y):x2+y2≤b2anda2x2​+b2y2​≤1}=18π Then, the value of (a −-− b)2 is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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