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Structure of Atom question

2022 · 26 Jun · Shift 2 · Q1
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Structure of Atom question

2022 · 26 Jun · Shift 2 · Q1

JEE MainChemistryStructure of AtomMCQ+4 / −1
The number of radial and angular nodes in 4d orbital are, respectively
  1. A
    1 and 2
  2. B
    3 and 2
  3. C
    1 and 0
  4. D
    2 and 1
View written solutionFree

Correct answer: A

  1. For an orbital with quantum numbers nnn and lll:

    • Number of radial nodes =n−l−1= n-l-1=n−l−1
    • Number of angular nodes =l= l=l

  2. For a 4d4d4d orbital:

    • Principal quantum number: n=4n=4n=4
    • For a ddd orbital, azimuthal quantum number: l=2l=2l=2

  3. Calculate radial nodes: n−l−1=4−2−1=1n-l-1 = 4-2-1 = 1n−l−1=4−2−1=1

  4. Calculate angular nodes: l=2l=2l=2

  5. Therefore, the number of radial and angular nodes are: 1 and 21 \text{ and } 21 and 2

  6. Checking options:

    • A: 111 and 222 ✅
    • B: 333 and 222 ❌
    • C: 111 and 000 ❌
    • D: 222 and 111 ❌

Hence, the correct answer is Option A.

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