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Coordination Compounds question

2024 · 9 Apr · Shift 2 · Q19
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  5. /2024 · 9 Apr · Shift 2 · Q19

Coordination Compounds question

2024 · 9 Apr · Shift 2 · Q19

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
The coordination environment of Ca2+\mathrm{Ca}^{2+}Ca2+ ion in its complex with EDTA4−\mathrm{EDTA}^{4-}EDTA4− is :
  1. A
    trigonal prismatic
  2. B
    octahedral
  3. C
    square planar
  4. D
    tetrahedral
View written solutionFree

Correct answer: B

  1. Identify the ligand and its denticity

    EDTA is ethylenediaminetetraacetate, written as EDTA4−\mathrm{EDTA}^{4-}EDTA4−. It is a hexadentate ligand, meaning it can donate 6 pairs of electrons to a metal ion:

    • 2 from nitrogen atoms
    • 4 from carboxylate oxygen atoms

    So, when Ca2+\mathrm{Ca}^{2+}Ca2+ binds with EDTA4−\mathrm{EDTA}^{4-}EDTA4−, the metal ion is surrounded by 6 donor atoms.

  2. Determine the coordination number

    Since EDTA binds through 6 donor atoms, the coordination number of Ca2+\mathrm{Ca}^{2+}Ca2+ in this complex is:

    Coordination number=6\text{Coordination number} = 6Coordination number=6

  3. Relate coordination number to geometry

    The most common geometry for coordination number 6 is octahedral.

    Thus, the coordination environment of Ca2+\mathrm{Ca}^{2+}Ca2+ in [Ca(EDTA)]2−[\mathrm{Ca}(\mathrm{EDTA})]^{2-}[Ca(EDTA)]2− is:

    octahedral\boxed{\text{octahedral}}octahedral​

  4. Check options

    • A: trigonal prismatic →\rightarrow→ not the usual geometry here
    • B: octahedral →\rightarrow→ correct
    • C: square planar →\rightarrow→ usually coordination number 4
    • D: tetrahedral →\rightarrow→ usually coordination number 4
  5. Final answer

    The correct option is:

    B: octahedral\boxed{\text{B: octahedral}}B: octahedral​

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