Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Chemical Equilibrium question

2014 · Shift 0 · Q5
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Chemical Equilibrium
  5. /2014 · Shift 0 · Q5

Chemical Equilibrium question

2014 · Shift 0 · Q5

JEE MainChemistryChemical EquilibriumMCQ+4 / −1
For the reaction SO2SO_2SO2​ (g) + 12O2(g)⇋{1 \over 2} O_2(g) \leftrightharpoons21​O2​(g)⇋ SO3SO_3SO3​(g). if KP = KC(RT)x where the symbols have usual meaning then the value of x is: (assuming ideality)
  1. A
    -1
  2. B
    -1/2
  3. C
    1/2
  4. D
    1
View written solutionFree

Correct answer: B

  1. For gaseous equilibria, the relation between KPK_PKP​ and KCK_CKC​ is

KP=KC(RT)ΔnK_P = K_C (RT)^{\Delta n}KP​=KC​(RT)Δn

where

Δn=(moles of gaseous products)−(moles of gaseous reactants)\Delta n = (\text{moles of gaseous products}) - (\text{moles of gaseous reactants})Δn=(moles of gaseous products)−(moles of gaseous reactants)

  1. Given reaction:

SO2(g)+12O2(g)⇌SO3(g)SO_2(g) + \frac{1}{2}O_2(g) \rightleftharpoons SO_3(g)SO2​(g)+21​O2​(g)⇌SO3​(g)

  1. Count gaseous moles:
  • Products: 111 mole of SO3SO_3SO3​
  • Reactants: 111 mole of SO2+12SO_2 + \frac{1}{2}SO2​+21​ mole of O2=32O_2 = \frac{3}{2}O2​=23​ moles

So,

Δn=1−32=−12\Delta n = 1 - \frac{3}{2} = -\frac{1}{2}Δn=1−23​=−21​

  1. Therefore,

KP=KC(RT)−1/2K_P = K_C (RT)^{-1/2}KP​=KC​(RT)−1/2

Hence, comparing with

KP=KC(RT)xK_P = K_C (RT)^xKP​=KC​(RT)x

we get

x=−12x = -\frac{1}{2}x=−21​

  1. Option check:
  • A: −1-1−1 ❌
  • B: −12-\frac{1}{2}−21​ ✅
  • C: 12\frac{1}{2}21​ ❌
  • D: 111 ❌

Therefore, the correct answer is B.

PreviousNext

More from Chemical Equilibrium

  • The equilibrium constant (KC) for the reaction N2​(g) + O2​(g) → 2NO(g) at temperature T is 4 × 10–4. The value of KC for the reaction, NO(g) → 1/2N2​(g) + 1/2O2​(g) at the same temperature is :2012 · MCQ
  • A vessel at 1000 K contains CO2​ with a pressure of 0.5 atm. Some of the CO2​ is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is :2011 · MCQ
  • In aqueous solution the ionization constants for carbonic acid are K1 = 4.2 x 10–7 and K2 = 4.8 x 10–11 Select the correct statement for a saturated 0.034 M solution of the carbonic acid.2010 · MCQ
  • For the following three reactions a, b and c, equilibrium constants are given: a. CO (g) + H2​O (g) ⇋ CO2​(g) + H2​ (g) ; K1 b. CH4​ (g) + H2​O (g) ⇋ CO(g) + 3H2​ (g) ; K2 c. CH4​…2008 · MCQ
  • The equilibrium constants KP1 and KP2 for the reactions X ⇋ 2Y and Z ⇋ P + Q, respectively are in the ratio of 1 : 9. If the degree of dissociation of X and Z be equal then the ratio of total…2008 · MCQ
  • Phosphorus pentachloride dissociates as follows, in a closed reaction vessel PCl5​ (g) ⇋ PCl3​ (g) + Cl2​ (g) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl5​ is…2006 · MCQ
  • The equilibrium constant for the reaction SO3​ (g) ⇋ SO2​ (g) + 21​ O2​ (g) is Kc = 4.9 × 10–2. The value of Kc for the reaction 2SO2​ (g) + O2​ (g) ⇋ 2SO3​ (g) will be :2006 · MCQ
  • An amount of solid NH4​HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm. Pressure. Ammonium hydrogen sulphide decomposes to yield NH3​ and H2​S gases in the flask. When the decomposition…2005 · MCQ