1. Identify the reactions of glucose with each reagent

Glucose is an aldohexose. It shows reactions characteristic of both an aldehyde group and multiple hydroxyl groups.

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2. Match (A): Glucose / $\mathrm{NaHCO_3}/\Delta$

$\mathrm{NaHCO_3}$ reacts with acids stronger than carbonic acid, releasing $\mathrm{CO_2}$. Glucose is neither a carboxylic acid nor acidic enough to react with sodium bicarbonate.

Hence: $\text{Glucose} + \mathrm{NaHCO_3} \rightarrow \text{No reaction}$

So, $A \to II$

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3. Match (B): Glucose / $\mathrm{HNO_3}$

Nitric acid is a strong oxidizing agent. It oxidizes both:

• the aldehyde group at C-1, and
• the terminal primary alcohol group at C-6

Thus glucose gives the dicarboxylic acid, called saccharic acid.

So, $B \to IV$

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4. Match (C): Glucose / $\mathrm{HI}/\Delta$

On prolonged heating with excess HI, glucose is completely reduced to the straight-chain hydrocarbon having 6 carbon atoms: $\text{Glucose} \xrightarrow[\Delta]{\mathrm{HI}} \text{n-hexane}$

So, $C \to III$

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5. Match (D): Glucose / Bromine water

Bromine water is a mild oxidizing agent. It oxidizes only the aldehyde group of glucose to the corresponding carboxylic acid, gluconic acid.

So, $D \to I$

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6. Final matching

Thus the correct correspondence is:

• $A \to II$
• $B \to IV$
• $C \to III$
• $D \to I$

This matches Option A.

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7. Comparison with stored answer

Stored correct answer: A

Derived answer: A

Hence, the derived answer agrees with the stored answer.