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Basics of Organic Chemistry question

2024 · 9 Apr · Shift 2 · Q8
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Basics of Organic Chemistry question

2024 · 9 Apr · Shift 2 · Q8

JEE MainChemistryBasics of Organic ChemistryMCQ+4 / −1
Total number of stereo isomers possible for the given structure : JEE Main 2024 (Online) 9th April Evening Shift Chemistry - Basics of Organic Chemistry Question 61 English
  1. A
    4
  2. B
    2
  3. C
    8
  4. D
    3
View written solutionFree

Correct answer: C

The question asks for the total number of stereoisomers possible for the given structure, but the actual structure/image is missing from the prompt.

Without the molecular structure, the number of stereoisomers cannot be derived reliably, because it depends on features such as:

  1. Number of chiral centers
  2. Presence or absence of symmetry
  3. Possibility of meso forms
  4. Geometrical isomerism (E/ZE/ZE/Z, cis/trans)
  5. Restricted rotation or other stereogenic elements

So a step-by-step stereoisomer count is not possible from the text alone.

What would normally be done

For a structure, we would:

  1. Identify all stereogenic centers.
  2. Compute the maximum possible stereoisomers as 2n2^n2n for nnn independent chiral centers.
  3. Check for symmetry to subtract meso/redundant forms.
  4. Include any geometrical isomerism if present.

For example:

  • If there are 222 independent chiral centers and no symmetry, total stereoisomers =22=4=2^2=4=22=4.
  • If there are 333 independent chiral centers and no symmetry, total stereoisomers =23=8=2^3=8=23=8.

Since the stored answer is C = 8, that would typically correspond to a structure having three independent stereogenic elements and no internal symmetry. But this cannot be confirmed without seeing the structure.

Conclusion

Because the structure is absent, the answer cannot be independently verified from the provided information.

However, if I must compare with the stored key, the stored answer is C (8).

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