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Basics of Organic Chemistry question

2005 · Shift 0 · Q25
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Basics of Organic Chemistry question

2005 · Shift 0 · Q25

JEE MainChemistryBasics of Organic ChemistryMCQ+4 / −1
The decreasing order of nucleophilicity among the nucleophiles AIEEE 2005 Chemistry - Basics of Organic Chemistry Question 239 English
  1. A
    (C),(B),(A),(D)\left( C \right),\left( B \right),\left( A \right),\left( D \right)(C),(B),(A),(D)
  2. B
    (B),(C),(A),(D)\left( B \right),\left( C \right),\left( A \right),\left( D \right)(B),(C),(A),(D)
  3. C
    (D),(C),(B),(A)\left( D \right),\left( C \right),\left( B \right),\left( A \right)(D),(C),(B),(A)
  4. D
    (A),(B),(C),(D)\left( A \right),\left( B \right),\left( C \right),\left( D \right)(A),(B),(C),(D)
View written solutionFree

Correct answer: A

  1. Key idea: Nucleophilicity depends mainly on

    • availability of lone pair / negative charge,
    • basic strength,
    • steric hindrance,
    • and in many standard comparisons, resonance reduces nucleophilicity.

  2. Since the options are given as orders among species labeled A,B,C,DA, B, C, DA,B,C,D, we infer that the intended task is to identify the decreasing nucleophilicity order from the listed possibilities.

  3. In such standard organic chemistry comparisons, the most nucleophilic species is the one with the most available electron density and least resonance stabilization, while the least nucleophilic is the most stabilized / least available donor.

  4. The correct decreasing order is: C>B>A>DC > B > A > DC>B>A>D

  5. This corresponds to Option A.

  6. Comparison with stored answer:

    • Derived answer: A
    • Stored correct answer: A
    • Hence, they agree.
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