1. Reaction in Tollen's test

An aldehyde reduces Tollen's reagent:

$\text{RCHO} + 2[Ag(NH_3)_2]^+ + 3OH^- \rightarrow \text{RCOO}^- + 2Ag + 4NH_3 + 2H_2O$

So, 1 mole of aldehyde produces 4 moles of $NH_3$.

2. Molar mass of cyclohexanecarbaldehyde

Cyclohexanecarbaldehyde has structure $C_6H_{11}CHO$, i.e. molecular formula:

$C_7H_{12}O$

Its molar mass is:

$7(12) + 12(1) + 16 = 84 + 12 + 16 = 112\,\text{g/mol}$

3. Moles of cyclohexanecarbaldehyde

Given mass = $131.8\,\text{kg} = 131800\,\text{g}$

$n = \frac{131800}{112} = 1176.7857\,\text{mol}$

4. Moles of $NH_3$ formed

Using the stoichiometric ratio:

$1\,\text{mol aldehyde} \rightarrow 4\,\text{mol } NH_3$

$n(NH_3) = 4 \times 1176.7857 = 4707.1428\,\text{mol}$

5. Mass of $NH_3$ formed

Molar mass of $NH_3$:

$14 + 3(1) = 17\,\text{g/mol}$

So mass is:

$m = 4707.1428 \times 17 = 80021.43\,\text{g}$

$= 80.021\,\text{kg}$

Nearest integer:

$\boxed{80}$

6. Comparison with stored answer

Stored correct answer = $60$

But from standard Tollen's test stoichiometry, the correct value is $\boxed{80}$ kg.

So the stored answer appears to be incorrect.