
- A(i) ; (ii) /; (iii)
- B(i) ; (ii)
- C(i) ; (ii) ; (iii)
- D(i) ; (ii) Raney Ni/; (iii)
View written solutionFree
Correct answer: A
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Identify the intended transformation
From the reagent options, the conversion is the standard one where a nitrile is first converted to an imine salt (Stephen reduction), which on hydrolysis gives an aldehyde.
The key reagent set for this is:
If the starting compound is a carboxylic acid derivative needing prior conversion to nitrile/related reducible intermediate, is consistent with the sequence used in such standard conversions.
-
Check each option
Option A
- followed by hydrolysis is the Stephen reduction condition, which converts nitriles into aldehydes.
- This is the only option containing the characteristic reagent combination for aldehyde formation from a nitrile.
- Hence, this option is consistent with the required conversion.
✅ Option A is correct.
Option B
- is a strong reducing agent.
- It reduces nitriles, acids, esters, etc. generally to primary alcohols or amines, not selectively to aldehydes.
- Therefore it does not fit the required conversion.
❌ Option B is incorrect.
Option C
- DIBAL-H can reduce nitriles/esters to aldehydes under controlled conditions.
- However, the presence of prior makes this sequence unsuitable for the standard conversion implied here.
- This is not the expected reagent set for the asked transformation.
❌ Option C is incorrect.
Option D
- reduces aldehydes/ketones, but is not used for such conversion to aldehyde from nitrile/acid derivative.
- Raney Ni/ generally hydrogenates multiple bonds or can reduce nitriles further to amines, not aldehydes.
- Hence this sequence is unsuitable.
❌ Option D is incorrect.
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Final answer
The correct reagent sequence is:
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Comparison with stored answer
Stored correct answer: A
My derived answer: A
So, the derived answer agrees with the stored answer.
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