We need to identify which compound gives the corresponding hydrocarbon on reduction with zinc and hydrochloric acid.

The reagent combination Zn/HCl is used in Clemmensen reduction, which reduces: $\text{Aldehydes and ketones} \longrightarrow \text{hydrocarbons}$

In general: $R-CO-R' \xrightarrow[\text{HCl}]{\text{Zn(Hg)}} R-CH_2-R'$

Even when written as Zn/HCl in such questions, the intended reaction is the Clemmensen-type reduction of the carbonyl group.

Now check each option:

A. Ethyl acetate

• It is an ester: $CH_3COOC_2H_5$
• Esters are not reduced to hydrocarbons by Zn/HCl.
• So, incorrect.

B. Butan-2-one

• It is a ketone: $CH_3COCH_2CH_3$
• Ketones undergo Clemmensen reduction to hydrocarbons: $CH_3COCH_2CH_3 \xrightarrow[\text{HCl}]{\text{Zn}} CH_3CH_2CH_2CH_3$
• Product is butane, the corresponding hydrocarbon.
• So, correct.

C. Acetamide

• It is an amide: $CH_3CONH_2$
• Amides do not give the corresponding hydrocarbon with Zn/HCl.
• So, incorrect.

D. Acetic acid

• It is a carboxylic acid: $CH_3COOH$
• Carboxylic acids are not reduced to hydrocarbons by Zn/HCl.
• So, incorrect.

Therefore, the only compound that gives the corresponding hydrocarbon on reduction with Zn/HCl is: $\boxed{\text{Butan-2-one}}$

Comparison with stored correct answer:

• Derived answer: B
• Stored correct answer: B
• They match.