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Work Power and Energy question

2018 · Shift 1 · Q43
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Work Power and Energy question

2018 · Shift 1 · Q43

JEE AdvancedPhysicsWork Power and EnergyNumerical+3 / −1
A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is 2.0 Nm−12.0\,N{m^{ - 1}}2.0Nm−1 and the mass of the block is 2.0kg.2.0kg.2.0kg. Ignore the mass of the spring. Initially the spring is an unstretched condition. Another block of mass 1.0kg1.0kg1.0kg moving with a speed of 2.0ms−12.0m{s^{ - 1}}2.0ms−1 collides elastically with the first block. The collision is such that the 2.0kg2.0kg2.0kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is ‾\underline{\hspace{2cm}}​. JEE Advanced 2018 Paper 1 Offline Physics - Work Power & Energy Question 15 English
Numerical answer
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