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Simple Harmonic Motion question

2015 · Shift 1 · Q58
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Simple Harmonic Motion question

2015 · Shift 1 · Q58

JEE AdvancedPhysicsSimple Harmonic MotionMultiple correct+4 / −2
Two independent harmonic oscillators of equal masses are oscillating about the origin with angular frequencies ω\omegaω 1 and ω\omegaω 2 and have total energies E1 and E2, respectively. The variations of their momenta p with positions x are shown in the figures. If ab=n2{a \over b} = {n^2}ba​=n2 and aR=n{a \over R} = nRa​=n, then the correct equations is/are JEE Advanced 2015 Paper 1 Offline Physics - Simple Harmonic Motion Question 19 English
  1. A
    E1 ω\omegaω 1 = E2 ω\omegaω 2
  2. B
    ω2ω1=n2{{{\omega _2}} \over {{\omega _1}}} = {n^2}ω1​ω2​​=n2
  3. C
    ω1ω2=n2{\omega _1}{\omega _2} = {n^2}ω1​ω2​=n2
  4. D
    E1ω1=E2ω2{{{E_1}} \over {{\omega _1}}} = {{{E_2}} \over {{\omega _2}}}ω1​E1​​=ω2​E2​​
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