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Vector Algebra question

2025 · Shift 2 · Q28
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  5. /2025 · Shift 2 · Q28

Vector Algebra question

2025 · Shift 2 · Q28

JEE AdvancedMathematicsVector AlgebraNumerical+4 / −1
Consider the vectors x⃗=ı^+2ȷ^+3k^,y⃗=2ı^+3ȷ^+k^, and z⃗=3ı^+ȷ^+2k^\vec{x}=\hat{\imath}+2 \hat{\jmath}+3 \hat{k}, \quad \vec{y}=2 \hat{\imath}+3 \hat{\jmath}+\hat{k}, \quad \text { and } \quad \vec{z}=3 \hat{\imath}+\hat{\jmath}+2 \hat{k}x=^+2^​+3k^,y​=2^+3^​+k^, and z=3^+^​+2k^ For two distinct positive real numbers α\alphaα and β\betaβ, define X⃗=αx⃗+βy⃗−z⃗,Y⃗=αy⃗+βz⃗−x⃗, and Z⃗=αz⃗+βx⃗−y⃗.\vec{X}=\alpha \vec{x}+\beta \vec{y}-\vec{z}, \quad \vec{Y}=\alpha \vec{y}+\beta \vec{z}-\vec{x}, \quad \text { and } \quad \vec{Z}=\alpha \vec{z}+\beta \vec{x}-\vec{y} .X=αx+βy​−z,Y=αy​+βz−x, and Z=αz+βx−y​. If the vectors X⃗,Y⃗\vec{X}, \vec{Y}X,Y, and Z⃗\vec{Z}Z lie in a plane, then the value of α+β−3\alpha+\beta-3α+β−3 is ‾\underline{\hspace{2cm}}​.
Numerical answer
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