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Matrices and Determinants question

2024 · Shift 1 · Q31
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  5. /2024 · Shift 1 · Q31

Matrices and Determinants question

2024 · Shift 1 · Q31

JEE AdvancedMathematicsMatrices and DeterminantsMCQ+3 / −1
Let α\alphaα and β\betaβ be the distinct roots of the equation x2+x−1=0x^2+x-1=0x2+x−1=0. Consider the set T={1,α,β}T=\{1, \alpha, \beta\}T={1,α,β}. For a 3×33 \times 33×3 matrix M=(aij)3×3M=\left(a_{i j}\right)_{3 \times 3}M=(aij​)3×3​, define Ri=ai1+ai2+ai3R_i=a_{i 1}+a_{i 2}+a_{i 3}Ri​=ai1​+ai2​+ai3​ and Cj=a1j+a2j+a3jC_j=a_{1 j}+a_{2 j}+a_{3 j}Cj​=a1j​+a2j​+a3j​ for i=1,2,3i=1,2,3i=1,2,3 and j=1,2,3j=1,2,3j=1,2,3.

Match each entry in List-I to the correct entry in List-II.

List-I List-II
(P) The number of matrices M=(aij)3x3M = (a_{ij})_{3x3}M=(aij​)3x3​ with all entries in TTT such that Ri=Cj=0R_i = C_j = 0Ri​=Cj​=0 for all i,ji, ji,j, is (1) 1
(Q) The number of symmetric matrices M=(aij)3x3M = (a_{ij})_{3x3}M=(aij​)3x3​ with all entries in TTT such that Cj=0C_j = 0Cj​=0 for all jjj, is (2) 12
(R) Let M=(aij)3x3M = (a_{ij})_{3x3}M=(aij​)3x3​ be a skew symmetric matrix such that aij∈Ta_{ij} \in Taij​∈T for i>ji \gt ji>j.

Then the number of elements in the set

{(xyz):x,y,z∈R,M(xyz)=(a120a13)}\left\{ \begin{pmatrix} x \\ y \\ z \end{pmatrix} : x, y, z \in \mathbb{R}, M \begin{pmatrix} x \\ y \\ z \end{pmatrix} = \begin{pmatrix} a_{12} \\ 0 \\ a_{13} \end{pmatrix} \right\}⎩⎨⎧​​xyz​​:x,y,z∈R,M​xyz​​=​a12​0a13​​​⎭⎬⎫​ is
(3) infinite
(S) Let M=(aij)3x3M = (a_{ij})_{3x3}M=(aij​)3x3​ be a matrix with all entries in TTT such that Ri=0R_i = 0Ri​=0 for all iii. Then the absolute value of the determinant of MMM is (4) 6

The correct option is
  1. A
    (P) →\rightarrow→(4) \quad(Q) →(2)(R)→(5)\rightarrow(2) \quad(\mathrm{R}) \rightarrow(5) \quad→(2)(R)→(5)(S) →\rightarrow→ (1)
  2. B
    (P)→(2)(Q)→(4)(R)→(1)(S)→(5)(\mathrm{P}) \rightarrow(2) \quad(\mathrm{Q}) \rightarrow(4) \quad(\mathrm{R}) \rightarrow(1) \quad(\mathrm{S}) \rightarrow(5)(P)→(2)(Q)→(4)(R)→(1)(S)→(5)
  3. C
    (P)→(2)(\mathrm{P}) \rightarrow(2) \quad(P)→(2)(Q) →(4)(R)→(3)\rightarrow(4) \quad(\mathrm{R}) \rightarrow(3) \quad→(4)(R)→(3)(S) →\rightarrow→ (5)
  4. D
    (P) →\rightarrow→(1) \quad(Q) →\rightarrow→(5) \quad(R) →\rightarrow→(3) \quad(S) →\rightarrow→ (4)
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