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Matrices and Determinants question

2019 · Shift 1 · Q20
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  5. /2019 · Shift 1 · Q20

Matrices and Determinants question

2019 · Shift 1 · Q20

JEE AdvancedMathematicsMatrices and DeterminantsMCQ+3 / −1
Let M=[sin⁡4θ1+cos⁡2θ−1−sin⁡2θcos⁡4θ]=αI+βM−1M = \left[ {\begin{matrix} {{{\sin }^4}\theta } \\ {1 + {{\cos }^2}\theta } \\ \end{matrix} \begin{matrix} { - 1 - {{\sin }^2}\theta } \\ {{{\cos }^4}\theta } \\ \end{matrix} } \right] = \alpha I + \beta {M^{ - 1}}M=[sin4θ1+cos2θ​−1−sin2θcos4θ​]=αI+βM−1, where α\alphaα=α\alphaα(θ\thetaθ) and β\betaβ=β\betaβ(θ\thetaθ) are real numbers, and I is the 2 ×\times× 2 identity matrix. If α\alphaα* is the minimum of the set {}α\alphaα(θ\thetaθ) : θ∈\theta \inθ∈ [0, 2 π\piπ)} and {β\betaβ(θ\thetaθ) : θ∈\theta \inθ∈ [0, 2 π\piπ{)}, then the value of α\alphaα* + β\betaβ* is
  1. A
    −1716- {{17} \over {16}}−1617​
  2. B
    −3116- {{31} \over {16}}−1631​
  3. C
    −3716- {{37} \over {16}}−1637​
  4. D
    −2916- {{29} \over {16}}−1629​
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