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Limits Continuity and Differentiability question

2017 · Shift 2 · Q30
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  2. /JEE Advanced
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  4. /Limits Continuity and Differentiability
  5. /2017 · Shift 2 · Q30

Limits Continuity and Differentiability question

2017 · Shift 2 · Q30

JEE AdvancedMathematicsLimits Continuity and DifferentiabilityMultiple correct+4 / −2
Let f(x)=1−x(1+∣1−x∣)∣1−x∣cos⁡(11−x)f(x) = {{1 - x(1 + |1 - x|)} \over {|1 - x|}}\cos \left( {{1 \over {1 - x}}} \right)f(x)=∣1−x∣1−x(1+∣1−x∣)​cos(1−x1​) for x eee 1. Then
  1. A
    lim⁡x→1+f(x)\mathop {\lim }\limits_{x \to {1^ + }} f(x)x→1+lim​f(x) = 0
  2. B
    lim⁡x→1−f(x)\mathop {\lim }\limits_{x \to {1^ - }} f(x)x→1−lim​f(x) does not exist
  3. C
    lim⁡x→1−f(x)\mathop {\lim }\limits_{x \to {1^ - }} f(x)x→1−lim​f(x) = 0
  4. D
    lim⁡x→1+f(x)\mathop {\lim }\limits_{x \to {1^ + }} f(x)x→1+lim​f(x) does not exist
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