Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Aldehydes Ketones and Carboxylic Acids question

2011 · Shift 1 · Q17
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Advanced
  3. /Chemistry
  4. /Aldehydes Ketones and Carboxylic Acids
  5. /2011 · Shift 1 · Q17

Aldehydes Ketones and Carboxylic Acids question

2011 · Shift 1 · Q17

JEE AdvancedChemistryAldehydes Ketones and Carboxylic AcidsMCQ+3 / −1
An acyclic hydrocarbon P, having molecular formula C6H10{}_{10}10​, gave acetone as the only organic product through the following sequence of reactions, in which Q is an intermediate organic compound. IIT-JEE 2011 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 26 English ComprehensionThe structure of the compound Q is
  1. A
    IIT-JEE 2011 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 26 English Option 1
  2. B
    IIT-JEE 2011 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 26 English Option 2
  3. C
    IIT-JEE 2011 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 26 English Option 3
  4. D
    IIT-JEE 2011 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 26 English Option 4
View written solutionFree

Correct answer: B

Step-by-step Derivation

The problem asks for the structure of an intermediate organic compound Q in a two-step reaction sequence starting from an acyclic hydrocarbon P (C₆H₁₀).

The sequence of reactions is:

P (C6H10)→(i) conc. H2SO4 (aq),H2OQ→(ii) O3 (iii) Zn,H2OAcetone (only)P~(C_6H_{10}) \xrightarrow{(i)~conc.~H_2SO_4~(aq), H_2O} Q \xrightarrow{(ii)~O_3~(iii)~Zn, H_2O} \text{Acetone (only)}P (C6​H10​)(i) conc. H2​SO4​ (aq),H2​O​Q(ii) O3​ (iii) Zn,H2​O​Acetone (only)

  1. Analyze the second reaction (Ozonolysis of Q): The second step is the reductive ozonolysis of the intermediate Q. Reductive ozonolysis (using O₃ followed by Zn/H₂O) cleaves carbon-carbon double bonds (C=C). Each carbon atom of the double bond is converted into a carbonyl group (C=O).

  2. Determine the structure of Q from the ozonolysis product: The problem states that the only organic product of this reaction is acetone. The structure of acetone is: CH3−CO−CH3Acetoneor(CH3)2C=O\underset{\text{Acetone}}{CH_3-CO-CH_3} \quad \text{or} \quad (CH_3)_2C=OAcetoneCH3​−CO−CH3​​or(CH3​)2​C=O For the ozonolysis of an alkene to yield a single product, the alkene must be symmetrical with respect to its double bond. To produce only acetone, both carbons of the double bond in Q must be bonded to two methyl groups each. We can deduce the structure of Q by conceptually reversing the ozonolysis reaction with two molecules of acetone: (CH3)2C=O+O=C(CH3)2⟶(CH3)2C=C(CH3)2+[O2](CH_3)_2C=O + O=C(CH_3)_2 \longrightarrow (CH_3)_2C=C(CH_3)_2 + [O_2](CH3​)2​C=O+O=C(CH3​)2​⟶(CH3​)2​C=C(CH3​)2​+[O2​] Thus, the structure of the intermediate Q must be 2,3-dimethylbut-2-ene. The reaction is: (CH3)2C=C(CH3)2→(i) O3 (ii) Zn,H2O2 (CH3)2C=O(CH_3)_2C=C(CH_3)_2 \xrightarrow{(i)~O_3~(ii)~Zn, H_2O} 2~(CH_3)_2C=O(CH3​)2​C=C(CH3​)2​(i) O3​ (ii) Zn,H2​O​2 (CH3​)2​C=O

  3. Compare the deduced structure of Q with the given options: Let's examine the provided options:

    • A: (CH3)2CH-C≡C-CH3 (4-methylpent-2-yne)
    • B: (CH3)2C=C(CH3)2 (2,3-dimethylbut-2-ene)
    • C: (CH3)3C-C≡CH (3,3-dimethylbut-1-yne)
    • D: (CH3)2CH-CH=CH-CH3 (4-methylpent-2-ene)

    Our deduced structure for Q, 2,3-dimethylbut-2-ene, perfectly matches Option B.

  4. Verification and analysis of the first step (optional but good practice): The first step describes the conversion of P (C₆H₁₀) to Q (C₆H₁₂) using conc. H₂SO₄ (aq), H₂O. The molecular formula changes from C₆H₁₀ to C₆H₁₂. This corresponds to the addition of H₂ (a reduction), not H₂O (hydration). The given reagents (aqueous sulfuric acid) do not typically perform this reduction. This suggests a likely error in the problem statement for the first step. However, the information from the second step is unambiguous and sufficient to determine the structure of Q.

    If we were to perform ozonolysis on option D (4-methylpent-2-ene), the products would be isobutyraldehyde and acetaldehyde, not just acetone. (CH3)2CH−CH=CH−CH3→O3,Zn/H2O(CH3)2CH−CHO+CH3−CHO(CH_3)_2CH-CH=CH-CH_3 \xrightarrow{O_3, Zn/H_2O} (CH_3)_2CH-CHO + CH_3-CHO(CH3​)2​CH−CH=CH−CH3​O3​,Zn/H2​O​(CH3​)2​CH−CHO+CH3​−CHO

    Therefore, based on the definitive result of the ozonolysis reaction, Q must be 2,3-dimethylbut-2-ene.

Conclusion

The intermediate Q, upon ozonolysis, gives only acetone. This uniquely identifies Q as 2,3-dimethylbut-2-ene. This structure corresponds to option B.

PreviousNext

More from Aldehydes Ketones and Carboxylic Acids

  • In the scheme given below, the total number of intra molecular aldol condensation products formed from Y is ​. Includes diagram2010 · Numerical
  • Amongst the following, the total number of compounds soluble in aqueous NaOH is ​. Includes diagram2010 · Numerical
  • Two aliphatic aldehydes P and Q react in the presence of aqueous K2​CO3​ to give compound R, which upon treatment with HCN provides compound S. On acidification and… Includes diagram2010 · MCQ
  • Two aliphatic aldehydes P and Q react in the presence of aqueous K2​CO3​ to give compound R, which upon treatment with HCN provides compound S. On acidification and… Includes diagram2010 · MCQ
  • Two aliphatic aldehydes P and Q react in the presence of aqueous K2​CO3​ to give compound R, which upon treatment with HCN provides compound S. On acidification and… Includes diagram2010 · MCQ
  • A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give… Includes diagram2009 · MCQ
  • A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to… Includes diagram2009 · MCQ
  • A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to… Includes diagram2009 · MCQ