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Spectroscopy question

2015 · Q54
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Spectroscopy question

2015 · Q54

IIT JAMChemistrySpectroscopyNumerical+2 / −0
The magnetic field (in Tesla) required for flipping a 1^11 H nucleus in an NMR spectrometer operating at 400 MHz is ‾\underline{\hspace{2cm}}​ [Given: γ=2.67×108\gamma = 2.67 \times 10^8γ=2.67×108 T −1^{-1}−1 s −1^{-1}−1, π=3.14\pi = 3.14π=3.14]
Numerical answer
View written solutionFree

Correct answer: 9.0, 10.0

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