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Solid State question

2019 · Q16
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Solid State question

2019 · Q16

IIT JAMChemistrySolid StateMCQ+2 / −0.67
The ratio of the nearest neighbor atomic distances in body-centered cubic (bcc) and face-centered cubic (fcc) crystals with the same unit cell edge length is
  1. A
    32\sqrt{\frac{3}{2}}23​​
  2. B
    32\frac{\sqrt{3}}{2}23​​
  3. C
    12\frac{1}{\sqrt{2}}2​1​
  4. D
    12\frac{1}{2}21​
View written solutionFree

Correct answer: A

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