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Gaseous State question

2018 · Q49
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Gaseous State question

2018 · Q49

IIT JAMChemistryGaseous StateNumerical+1 / −0
The value of CvC_vCv​ for 1 mol of N 2_22​ gas predicted from the principle of equipartition of energy, ignoring vibrational contribution, is J K −1^{-1}−1 mol −1^{-1}−1 (rounded up to two decimal places). [R=8.3 JK−1 mol−1][R = 8.3 \text{ JK}^{-1} \text{ mol}^{-1}][R=8.3 JK−1 mol−1]
Numerical answer
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Correct answer: 20.00, 21.00

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