IIT JAMChemistryElectrochemistryNumerical+2 / −0
For the reaction, CuSO₄(aq) + Zn(s) → ZnSO₄(aq) + Cu(s), the value of ΔG° (in kJ mol⁻¹) is (Round off to the nearest integer)
(Reduction potential: Cu²⁺(aq)/Cu(s) = + 0.34 V; Zn²⁺(aq)/Zn(s) = - 0.76 V)
(Faraday constant = 96485 C mol⁻¹)
Numerical answer
View written solutionFree
Correct answer: -213, -211
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