IIT JAMChemistryChemical ThermodynamicsNumerical+2 / −0
One mole of an ideal gas is subjected to an isothermal increase in pressure from 100 kPa to 1000 kPa at 300 K. The change in Gibbs free energy of the system is kJ mol⁻¹. (Round off to one decimal place)
[Given: Gas constant (R) = 8.3 J K⁻¹ mol⁻¹]
Numerical answer
View written solutionFree
Correct answer: 5.6, 5.8
More from Chemical Thermodynamics
- The CORRECT expression that corresponds to reversible and adiabatic expansion of an ideal gas is2018 · MCQ
- The CORRECT expression(s) for isothermal expansion of 1 mol of an ideal gas is(are)2018 · Multiple correct
- Consider the reaction . The value of for the reaction at 300 K is -281.8 kJ mol . The value of at same temperature is kJ mol (rounded up to the…2018 · Numerical
- For the reaction , the following information is given T = 300 K kJ mol J K mol …2018 · Numerical
- A straight line having a slope of is obtained in a plot between2017 · MCQ
- Intensive variable(s) is/are2017 · Multiple correct
- At 298 K and 1 atm, the molar enthalpies of combustion of cyclopropane and propene are -2091 kJ mol⁻¹ and -2058 kJ mol⁻¹, respectively. The enthalpy change (in kJ mol⁻¹) for the conversion of one mole of propene to one mole of cyclopropane…2017 · Numerical
- Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of the system is increased from 5 atm to 30 atm at 300 K. The entropy change of the surroundings (in J K⁻¹) is …2017 · Numerical