IIT JAMChemistryBasic Concepts and StereochemistryNumerical+1 / −0
(R)-2-methyl-1-butanol has a specific rotation of +13.5°. The specific rotation of 2-methyl-1-butanol containing 40% of the (S)-enantiomer is °. (Round off to one decimal place)
Numerical answer
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Correct answer: 2.7
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