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Analytical Chemistry question

2018 · Q52
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Analytical Chemistry question

2018 · Q52

IIT JAMChemistryAnalytical ChemistryNumerical+2 / −0
24Na^{24}\text{Na}24Na decays to one-fourth of its initial amount in 29.8 hours. Its decay constant is hour −1^{-1}−1 (rounded up to four decimal places).
Numerical answer
View written solutionFree

Correct answer: 0.0460, 0.0470

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